It's almost 5:30am, I'm sleepy, so I wrote this up quickly, and it probably has a mistake somewhere, but at this hour I don't care

First, the probability that on some particular day (say Jan 1st) no students had their
birthday on it is : (probability 1st student wasn't born on Jan 1st) * (probability 2nd
student wasn't born on Jan 1st) * ... * (probability 2500th student wasn't born on Jan 1st)
= (364/365) ^ 2500 = 0.0010502
Now, if we add up
(probability no students had their birthday on Jan 1st) +
(probability no students had their birthday on Jan 2nd) +
(probability no students had their birthday on Jan 3rd) +
...
(probability no students had their birthday on Dec 31st)
= 0.0010502 * 365 = .383323
we will get the probability that there is at least one day in the year where no students had
their birthday. 1 minus that, is the probability that there is no such day, i.e. that on
every day someone has their birthday, which is what we want. So that will be 1 - .383323 =
.616677.